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Question
Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and ∠DAB = 60°. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.
Solution
Steps :
- Draw AB = 6 cm.
- At A draw ∠QAB = 60°.
- From AQ cut AD = 3 cm.
- From D, draw an arc of radius 6 cm.
- From B, draw an arc of radius 3 cm which meets the first arc at C.
- Join CD and BC.
Thus ABCD is the required ||gm. - Bisect ∠DAB, so that bisector meets CD at P.
- Join PB and measure ZAPB.
∴ ∠APB = 90°.
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