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Maharashtra State BoardSSC (English Medium) 7th Standard

Construct a triangle of the measures given below. In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45° - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Construct a triangle of the measures given below.

In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°

Geometric Constructions

Solution

Using the angle sum property, we can find the third angle of the triangle FEG. 

∠F + ∠E + ∠G = 180°

⇒ 65° + ∠E + 45° = 180°

⇒ ∠E = 70°

Steps of construction:

  1. Draw a line EG = 6 cm.
  2. With E as a centre, draw ∠XEG = 70°.
  3. With G as a centre, draw ∠YGE = 45º.
  4. Let YG and XE meet at point F. 

∆FEG is the required triangle. 

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Chapter 1: Geometrical Constructions - Practice Set 4 [Page 6]

APPEARS IN

Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 1 Geometrical Constructions
Practice Set 4 | Q 3 | Page 6
Balbharati Integrated 7 Standard Part 1 [English Medium] Maharashtra State Board
Chapter 3.1 Geometrical Constructions
Practice Set 4 | Q 3. | Page 43

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