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Question
Construct a triangle PQR with sides QR = 7 cm, PQ = 6 cm and \[\angle\]PQR = 60º. Then construct another triangle whose sides are \[\frac{3}{5}\] of the corresponiding sides of ∆PQR.
Solution
Steps of Construction
Step 1. Draw a line segment QR = 7 cm.
Step 2. At B, draw
\[\angle\]YQR.
Step 6. Along QY, mark five points R1, R2, R3, R4 and R5 such that QR1 = R1R2 = R2R3 = R3R4 = R4R5 .
Step 7. Join RR5.
Step 8. From R3, draw R3R' || RR5 meeting QR at R'.
Step 9. From R', draw P'R' || PR meeting PQ in P'.
Here, ∆P'QR' is the required triangle whose sides are \[\frac{3}{5}\] of the corresponding sides of ∆PQR.
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