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Question
Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are `3/4` times the corresponding sides of ΔABC
Solution
Steps of Construction
Step 1: Draw a line segment BC = 7cm.
Step 2: At B, draw ∠XBC = 60°.
Step 3: With B as center and radius 6 cm, draw an arc cutting the ray BX at A.
Step 4: Join AC. Thus, ΔABC is the required triangle.
Step 5: Below BC, draw an acute angle ∠YBC.
`"Step 6: Along BY, mark four points " B_1 ,B_2 ,B_3 and B_4 " such that " BB_1 = B_1 B_2 = B_2 B_3 = B_3 B_4` .
Step 7: Join CB4 .
Step 8: From B3 , draw B3 C ' ||CB4 meeting BC at C ' ’.
Step 9: From C’, Draw A'C' || ACmeeting AB in A’.
Here. ΔA'BC ' is the required triangle whose sides are `3/4`times the corresponding sides of ΔABC.
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