Advertisements
Advertisements
Question
Define electric resonance.
Solution
When frequency of applied alternating source (ωr) is equal to natural frequency
`(1/sqrt"LC")`
of RLC circuit, the current in the circuit reaches its maximum value. Then the circuit is said to be in electrical resonance.
APPEARS IN
RELATED QUESTIONS
How will you define RMS value of an alternating current?
Define capacitive reactance. Give its units.
Predict the polarity of the capacitor in a closed circular loop when two bar magnets are moved as shown in the figure.
A capacitor is used in the primary circuit of an induction coil.
A choke coil in series with a lamp is connected to a dc line. The lamp is seen to shine brightly. Insertion of an iron core in the choke causes no change in the lamp’s brightness. Predict the corresponding observations if the connection is to an ac line.
An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance ‘R’ are connected in series to an ac source of potential difference ‘V’ volts as shown in figure. Potential difference across L, C and R is 40 V, 10 V and 40 V, respectively. The amplitude of current flowing through LCR series circuit is `10sqrt2` A. The impedance of the circuit is :
In young's double slit experiment `"d"/"D"`= 10-4 D (d = distance between slits, D = distance of screen from the slits). At a point P on the screen resulting intensity is equal to the intensity due to individual slit l0. Then the distance of point P from the central maximum is (λ = 6000 `"A"^°`)
A series CR circuit with R = 200 Ω and C = (50/π) µF is connected across an ac source of peak voltage ε0 = 100 V and frequency v = 50 Hz. Calculate (a) impedance of the circuit (Z), (b) phase angle (Φ), and (c) voltage across the resistor.
An alternating current I = 14 sin (100 πt) A passes through a series combination of a resistor of 30 Ω and an inductor of `(2/(5pi))` H. Taking `sqrt2` = 1.4 calculate the rms value of the voltage drops across the resistor and the inductor.
