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Question
Differentiate the following w. r. t. x. : x3 log x
Solution
Let y = (x3 log x)
Differentiating w.r.t. x, we get
`dy/dx = d/dx x^3 log x`
= `x^3 d/dx(logx) + (logx) d/dx(x^3)`
= `x^3xx1/x + (log x)(3x^2)`
= x2 + 3x2 log x
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