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Question
Discuss briefly de-mineralisation of water by ion exchange resin.
Solution
Demineralised water free from all soluble mineral salts is obtained by passing water successively through a cation exchange and an anion exchange resin.
In cation exchange process, \[\ce{H+}\] exchanges for \[\ce{Na+, Ca^{2+}, Mg^{2+}}\] and in the anion exchange process \[\ce{OH}\] exchanges for anions like \[\ce{CH, HCO3, SO2^{-}4}\], etc. \[\ce{H+}\] and \[\ce{OH-}\] released combine to form water.
\[\ce{H^{+} + OH- → H2O}\]
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RELATED QUESTIONS
Is demineralised or distilled water useful for drinking purposes? If not, how can it be made useful?
how can demineralised be obtained?
The oxide that gives \[\ce{H2O2}\] on treatment with dilute \[\ce{H2SO4}\] is ______.
Which of the following ions will cause hardness in water sample?
Hardness of water may be temporary or permanent. Permanent hardness is due to the presence of:
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(ii) Sulphates of \[\ce{Ca}\] and \[\ce{Mg}\] in water.
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\[\ce{PbS (s) + H2O2 (aq) ->}\]
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\[\ce{CO (g) + 2H2 (g) ->[Cobalt][Catalyst]}\]
Match the items in Column I with the relevant item in Column II.
| Column I | Column II |
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| (ii) Used in Calgon method | (b) perhydrol |
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| (d) propellant |
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