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Question
The oxide that gives \[\ce{H2O2}\] on treatment with dilute \[\ce{H2SO4}\] is ______.
Options
\[\ce{PbO2}\]
\[\ce{BaO2 . 8H2O + O2}\]
\[\ce{MnO2}\]
\[\ce{TiO2}\]
Solution
The oxide that gives \[\ce{H2O2}\] on treatment with dilute \[\ce{H2SO4}\] is \[\ce{BaO2 . 8H2O + O2}\].
Explanation:
Hydrogen peroxide is produced by acidifying barium peroxide and eliminating excess water by evaporation under low pressure.
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