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Each Equal Side of an Isosceles Triangle is 3cm Less than the Unequal Side. the Height of the Perpendicular from the Vertex to the Unequal Side is 3cm Less than the Equal Side. If the Area - Mathematics

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Question

Each equal side of an isosceles triangle is 3cm less than the unequal side. The height of the perpendicular from the vertex to the unequal side is 3cm less than the equal side. If the area of the isosceles triangle is 108cm2, find the perimeter of the triangle.

Sum

Solution

Let the unequal side of the Isosceles triangle = x
Then the equal side of the Isosceles triangle = x - 3
And the perpendicular to the unequal side from the opposite vertex = x - 6

We know that, Area of a Triangle

= `(1)/(2)"b.h"  "i.e"(1)/(2)("Base" xx "Height")`

∴ Area of the Isosceles Triangle

= `(1)/(2) xx(x - 6)`
= 108
⇒ x2 - 6x = 216
⇒ x2 - 6x - 216 = 0
⇒ x2 - 6x + 9 - 9 - 216 = 0
⇒ (x - 3)2 = 225
⇒ x - 3 = 15
⇒ x = 18
⇒ x - 3 = 15
⇒ Perimeter
= 18 + 15 + 15
= 48cm.

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Chapter 24: Perimeter and Area - Exercise 24.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 24 Perimeter and Area
Exercise 24.1 | Q 20
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