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Question
Evaluate: `(2^2)^0 + 2^-4 div 2^-6 + (1/2)^-3`
Solution
`(2^2)^0 + 2^-4 div 2^-6 + (1/2)^-3`
`= (4)^0 + (1/2)^4 div (1/2)^6 + (2/1)^3` (∵ a0 = 1)
`= 1 + (1/2 xx 1/2 xx 1/2 xx 1/2) div (1/2 xx 1/2 xx 1/2 xx 1/2 xx 1/2 xx 1/2) + (2/1 xx 2/1 xx 2/1)`
`= 1+ (1/2 xx 1/2 xx 1/2 xx 1/2 xx 2 xx 2 xx 2 xx 2 xx 2 xx 2) + 8`
= 1 + 4 + 8 = 13
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