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Evaluate: 273+0.0083+0.0643 - Mathematics

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Question

Evaluate:

`root(3)(27) + root(3)(0.008) + root(3)(0.064)`

Evaluate

Solution

We have, `root(3)(27) + root(3)(0.008) + root(3)(0.064)`

27 = 3 × 3 × 3 = 33

`\implies root(3)(27) = 3`

`0.008 = 8/1000`

And 8 = 2 × 2 × 2 = 23

`\implies root(3)(8) = 2`

Also, 1000 = 2 × 2 × 2 × 5 × 5 × 5 = (2 × 5)3 

`\implies root(3)(1000) = 2 xx 5 = 10`

∴ `root(3)(0.008) = (root(3)(8))/(root(3)(1000)) = 2/10 = 0.2`

`0.064 = 64/1000`

And 64 = 2 × 2 × 2 × 2 × 2 × 2 = (2 × 2)3

`\implies root(3)(64) = 2 xx 2 = 4`

And 1000 = 2 × 2 × 2 × 5 × 5 × 5 = (2 × 5)3 

`\implies root(3)(1000) = 2 xx 5 = 10`

∴ `root(3)(0.064) = (root(3)(64))/(root(3)(1000)) = 4/10 = 0.4`

Thus, `root(3)(27) + root(3)(0.008) + root(3)(0.064)`

= 3 + 0.2 + 0.4

= 3.6

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Chapter 3: Square-Square Root and Cube-Cube Root - Exercise [Page 96]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 3 Square-Square Root and Cube-Cube Root
Exercise | Q 135. | Page 96

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