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Evaluate: (6×1022×53)2×2527 - Mathematics

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Question

Evaluate:

`((6 xx 10)/(2^2 xx 5^3))^2 xx 25/27`

Sum

Solution

We have, `((6 xx 10)/(2^2 xx 5^3))^2 xx 25/27 = ((2 xx 3 xx 2 xx 5)/(2^2 xx 5^3)) xx 5^2/3^3`  ......[∵ 6 = 2 × 3 and 10 = 2 × 5]

= `((2^2 xx 3 xx 5)/(2^2 xx 5^3)) xx 5^2/3^3` 

= `(3/5^2) xx 5^2/3^3`  ......[∵ (a × b)m = am × bm]

= `3^2/5^4 xx 5^2/3^3` ......[∵ (am)n = amn]

= `1/(5^2 xx 3)`

= `1/(25 xx 3)`

= `1/75`

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Chapter 11: Exponents and Powers - Exercise [Page 346]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 11 Exponents and Powers
Exercise | Q 85. (e) | Page 346

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