English

Evaluate : 9^(5/2) - 3 Xx 8^0 - (1/81)^(-1/2) - Mathematics

Advertisements
Advertisements

Question

Evaluate : `9^(5/2) - 3 xx 8^0 - (1/81)^(-1/2)`

Sum

Solution

`9^(5/2) - 3 xx 8^0 - (1/81)^(-1/2)`

= `(3^2)^(5/2) - 3 xx 1 - (1/3^4)^(-1/2)`

= `3^( 2 xx 5/2 ) - 3 - 3^[- 4 xx (-1/2)]`

= 35 - 3 - 32
= 243 - 3 - 9
= 231

shaalaa.com
Handling Positive, Fraction, Negative and Zero Indices
  Is there an error in this question or solution?
Chapter 7: Indices (Exponents) - Exercise 7 (C) [Page 101]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (C) | Q 1.1 | Page 101
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×