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Evaluate the Following: ( 64 216 ) 2 3 × ( 16 36 ) − 3 2 - Mathematics

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Question

Evaluate the following:

`(64/216)^(2/3) xx (16/36)^(-3/2)`

Sum

Solution

`(64/216)^(2/3) xx (16/36)^(-3/2)`

= `(2^6/6^3)^(2/3) xx (2^4/6^2)^(-3/2)`

= `(2^6)^(2/3)/(6^3)^(2/3) xx (2^4)^(-3/2)/(6^2)^(-3/2)`

= `(2)^(6 xx 2/3)/(6)^(3 xx 2/3) xx (2)^(4 xx (-3/2))/(6^2)^(2 xx (-3/2))`        ......(Using (am)n = amn)

= `(2)^(2xx2)/(6)^2 xx (2)^(2 xx(-3))/(6)^-3`

= `(2)^4/(6)^2 xx (2)^-6/(6)^-3`        

= `(2)^4/(6)^2 xx (6)^3/(2)^6`    ......`("Using"  "a"^"m" = 1/"a"^"m")`

= = `(2)^4/(2)^6 xx (6)^3/(6)^2`

= `(2)^(4-6) xx (6)^(3 - 2)`     .....(Using am ÷ an = am-n)

= `(2)^-2 xx (6)^1`

= `(1)/(2^2) xx 6`

= `(1)/(4) xx 6`

= `(3)/(2)`.

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Handling Positive, Fraction, Negative and Zero Indices
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Chapter 9: Indices - Exercise 9.1

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Frank Mathematics [English] Class 9 ICSE
Chapter 9 Indices
Exercise 9.1 | Q 2.3
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