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Question
Evaluate the following limits, if necessary use l’Hôpital Rule:
`lim_(x -> oo) x/logx`
Solution
`lim_(x -> oo) x/logx` ......`[oo/oo "Indeterminate form"]`
Applying L’ Hôpital’s Rule
`lim_(x -> oo) 1/(1/x) = lim_(x -< oo)`
x = `oo`
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