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Question
Examine the collinearity of the following set of point:
A(3, −1), B(0, −3), C(12, 5)
Solution
Given : A(3, −1), B(0, − 3), C(12, 5)
∴ area of ΔABC = `1/2|(3, -1, 1),(0, -3, 1),(12, 5, 1)|`
= `1/2[3(-3 - 5) + 1(0 - 12) + 1(0 + 36)]`
= `1/2(-24 - 12 + 36)` = 0
∴ A, B, C are collinear.
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