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Question
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`(1 - 1/a)^3`
Sum
Solution
`(1 - 1/a)^3`
(a − b)3 = a3 − 3a2b + 3ab2 − b3
her taking a = 1 and b = `(1/a)`
= `(1)^3 - 3 xx (1)^2 xx (1/a) + 3 xx 1 xx (1/a)^2 - (1/a)^3`
= `1 - 3 xx 1/a + 3 xx 1/a^2 - 1/a^3`
= `1 - 3/a + 3/a^2 - 1/a^3`
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