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Question
Explain the shape of \[\ce{BrF5}\].
Solution
In \[\ce{BrF5}\] the central bromine atom has 7 valence electrons. It makes five bonds with the fluorine atom and one lone pair of electron is left. Due to the lone pair-bond pair repulsions, \[\ce{BrF5}\] makes a structure of square pyramidal geometry. Due to the distortion of fluorine ions, each fluorine ion makes an angle of 90°.
The square pyramidal shape of \[\ce{BrF5}\] is:
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