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Question
Stable form of C may be represented by the formula:
Options
C
C2
C3
C4
Solution
C2
Explanation:
The electronic configuration of \[\ce{C}\] is given as 1s2, 2s2, 2p6, 3s2, 3p5 which the electronic configuration of chlorine atom \[\ce{(Cl)}\]. It is unstable due to one unpaired electron in the p-subshell. Hence, the \[\ce{C2}\] will be the stable form of \[\ce{C}\] as it will form a dichloride molecule \[\ce{(Cl2)}\].
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