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Explain the spectral distribution of blackbody radiation. - Physics

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Question

Explain the spectral distribution of blackbody radiation.

Answer in Brief
Explain

Solution 1

All objects with a temperature above absolute zero (0 K, -273.15oC) emit energy in the form of electromagnetic radiation.

A blackbody is a theoretical or model body that absorbs all radiation falling on it, reflecting or transmitting none. It is a hypothetical object which is a “perfect” absorber and a “perfect” emitter of radiation over all wavelengths.

The spectral distribution of the thermal energy radiated by a blackbody (i.e. the pattern of the intensity of the radiation over a range of wavelengths or frequencies) depends only on its temperature. 

The characteristics of blackbody radiation can be described in terms of several laws:

  1.  Planck’s Law of blackbody radiation, a formula to determine the spectral energy density of the emission at each wavelength (Eλ) at a particular absolute temperature (T).
    `"E"_λ = (8pi"h c")/(λ^5 ("e"^("hc"//λ"kT")-1))` 
  2. Wien’s Displacement Law, which states that the frequency of the peak of the emission (fmax) increases linearly with absolute temperature (T). Conversely, as the temperature of the body increases, the wavelength at the emission peak decreases. 
    fmax α T
  3. Stefan–Boltzmann Law, which relates the total energy emitted (E) to the absolute temperature (T). 
    E α T4 

In the image above, notice that:

  • The blackbody radiation curves have quite a complex shape (described by Planck’s Law).
  • The spectral profile (or curve) at a specific temperature corresponds to a specific peak wavelength, and vice versa.
  • As the temperature of the blackbody increases, the peak wavelength decreases (Wien’s Law).
  • The intensity (or flux) at all wavelengths increases as the temperature of the blackbody increases.
  • The total energy being radiated (the area under the curve) increases rapidly as the temperature increases (Stefan–Boltzmann Law).
  • Although the intensity may be very low at very short or long wavelengths, at any temperature above absolute zero energy is theoretically emitted at all wavelengths (the blackbody radiation curves never reach zero).
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Solution 2

  1. The rate of emission per unit area or power per unit area of a surface is defined as a function of the wavelength λ of the emitted radiation.
  2. Scientists studied the energy distribution of blackbody radiation as a function of wavelength.
  3. By keeping the source of radiation (such as a cavity radiator) at different temperatures they measured the radiant power corresponding to different wavelengths. The measurements were represented graphically in the form of curves showing the variation of radiant power per unit area as a function of wavelength λ at different constant temperatures as shown in the figure. 
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Spectral Distribution of Blackbody Radiation
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Chapter 3: Kinetic Theory of gases and Radiation - Long Answer

APPEARS IN

SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 3 Kinetic Theory of gases and Radiation
Long Answer | Q 1
Balbharati Physics [English] 12 Standard HSC Maharashtra State Board
Chapter 3 Kinetic Theory of Gases and Radiation
Exercises | Q 9 | Page 73
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