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Question
Factorisation of – 3a2 + 3ab + 3ac is 3a(– a – b – c).
Options
True
False
Solution
This statement is False.
Explanation:
Let us factorize – 3a2 + 3ab + 3ac.
– 3a2 + 3ab + 3ac = 3(– a × a + a × b + a × c)
⇒ – 3a2 + 3ab + 3ac = 3a(– a + b + c)
But, 3a(– a + b + c) ≠ 3a(– a – b – c)
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