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Factorise: 5a2 - b2 - 4ab + 7a - 7b - Mathematics

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Question

Factorise:

5a2 - b2 - 4ab + 7a - 7b

Sum

Solution

5a2 - b2 - 4ab + 7a - 7b

= 4a2 + a2 - b2 - 4ab + 7a - 7b

= a2 - b2 + 4a2 - 4ab + 7a - 7b

= (a2 - b2) + 4a(a - b) + 7(a - b)

= (a - b)(a + b) + 4a(a - b) + 7(a - b)       ...[∵ a2 - b2 = (a + b)(a - b)]

= (a - b)[(a + b) + 4a + 7]

= (a - b)[a + b + 4a + 7]

= (a - b)[5a + b + 7]

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Chapter 5: Factorisation - Exercise 5 (E) [Page 76]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 5 Factorisation
Exercise 5 (E) | Q 12 | Page 76
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