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Question
Factorise by taking out the common factors :
2 (2x - 5y) (3x + 4y) - 6 (2x - 5y) (x - y)
Solution
2 (2x - 5y) (3x + 4y) - 6 (2x - 5y) (x - y)
Taking (2x - 5y) common from both terms
= (2x - 5y)[2(3x + 4y) - 6(x - y)]
= (2x - 5y)(6x + 8y - 6x + 6y)
= (2x - 5y)(8y + 6y)
= (2x - 5y)(14y)
= (2x - 5y)14y
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