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Question
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
Solution
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
= `(4"a"^2 + 1/(4"a"^2) - 2) - (6"a" - 3/(2"a"))`
= `(2"a" - 1/(2"a"))^2 - 3(2"a" - 1/(2"a"))`
= `(2"a" - 1/(2"a")) (2"a" - 1/(2"a") - 3)`
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