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Factorise: 9a (x − 2y)4 − 12a (x − 2y)3 - Mathematics

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Question

factorise:

9a (x − 2y)4 − 12a (x − 2y)3 

Sum

Solution

9a (x − 2y)4 − 12a (x − 2y)3

The common factors between the terms are:

  • a,
  • (x − 2y)3, (the lower power of (x−2y),
  • And the coefficients 9 and 12 have a common factor of 3.

Factor out 3a(x − 2y)3:

9a(x − 2y)4 − 12a(x − 2y)3 = 3a(x − 2y)3 (3(x − 2y) −4)

Simplify 3(x − 2y) −4:

3(x − 2y) −4 = 3x − 6y − 4

Thus, the expression becomes:

3a(x − 2y)3 (3x − 6y − 4)

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Chapter 13: Factorisation - Exercise 13 (F) [Page 163]

APPEARS IN

Selina Concise Mathematics [English] Class 8 ICSE
Chapter 13 Factorisation
Exercise 13 (F) | Q 1.5 | Page 163
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