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Question
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
Solution
2a(p2 + q2) + 4b(p2 + q2)
Here, the common factor is 2(p2 + q2)
Dividing throughtout by 2(p2 + q2), we get
`(2"a"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)) + (4"b"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)`
= a + 2b
∴ 2a(p2 + q2) + 4b(p2 + q2)
= 2(p2 + q2)(a + 2b).
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