Advertisements
Advertisements
प्रश्न
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
उत्तर
2a(p2 + q2) + 4b(p2 + q2)
Here, the common factor is 2(p2 + q2)
Dividing throughtout by 2(p2 + q2), we get
`(2"a"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)) + (4"b"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)`
= a + 2b
∴ 2a(p2 + q2) + 4b(p2 + q2)
= 2(p2 + q2)(a + 2b).
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
2x, 3x2, 4
Factorise the following expression:
6p − 12q
Factorise the following expression:
−16z + 20z3
Factorise the following expression:
− 4a2 + 4ab − 4 ca
Factorise.
x2 + xy + 8x + 8y
Factorise.
15xy − 6x + 5y − 2
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
20a12b2 − 15a8b4
Factorize the following:
20x3 − 40x2 + 80x
Factorize the following:
2x3y2 − 4x2y3 + 8xy4
Factorize the following:
a4b − 3a2b2 − 6ab3
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factorize the following:
ax2y + bxy2 + cxyz
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Factorise : 15x + 5
Factorise : 3x2 + 6x3
Factorise : 12abc - 6a2b2c2 + 3a3b3c3
Factorise : 4x(3x - 2y) - 2y(3x - 2y)
factorise : 35a3b2c + 42ab2c2
Factorise the following by taking out the common factors:
81(p + q)2 -9p - 9q
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
Factorise:
x4 + y4 - 6x2y2
Factorise:
4x4 + 25y4 + 19x2y2
