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Question
Factorise : a - b - 4a2 + 4b2
Solution
a - b - 4a2 + 4b2
= ( a - b ) - 4( a2 - b2 )
= ( a - b ) - 4( a - b )( a + b ) [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a - b )[ 1 - 4( a + b )]
= ( a - b )[ 1 - 4a - 4b ]
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