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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Factorise: 9a (x − 2y)4 − 12a (x − 2y)3 - Mathematics

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प्रश्न

factorise:

9a (x − 2y)4 − 12a (x − 2y)3 

योग

उत्तर

9a (x − 2y)4 − 12a (x − 2y)3

The common factors between the terms are:

  • a,
  • (x − 2y)3, (the lower power of (x−2y),
  • And the coefficients 9 and 12 have a common factor of 3.

Factor out 3a(x − 2y)3:

9a(x − 2y)4 − 12a(x − 2y)3 = 3a(x − 2y)3 (3(x − 2y) −4)

Simplify 3(x − 2y) −4:

3(x − 2y) −4 = 3x − 6y − 4

Thus, the expression becomes:

3a(x − 2y)3 (3x − 6y − 4)

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अध्याय 13: Factorisation - Exercise 13 (F) [पृष्ठ १६३]

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सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 13 Factorisation
Exercise 13 (F) | Q 1.5 | पृष्ठ १६३
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