Advertisements
Advertisements
प्रश्न
Find the common factors of the terms.
3x2y3, 10x3y2, 6x2y2z
योग
उत्तर
The given terms are 3x2y3, 10x3y2 and 6x2y2z.
3x2y3 = 3 × x × x × y × y × y
10x3y2 = 2 × 5 × x × x × x × y × y
6x2y2z = 2 × 3 × x × x × y × y × z
The common factors are x, x, y, y
And, x × x × y × y
= x2y2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorize the following:
5x − 15x2
Factorize the following:
72x6y7 − 96x7y6
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Find the value of : `[(6.7)^2 - (3.3)^2]/[6.7 - 3.3]`
factorise : (ax + by)2 + (bx - ay)2
factorise : m - 1 - (m-1)2 + am - a
Factorise: a2 - 0·36 b2
Factorise the following by taking out the common factors:
12a3 + 15a2b - 21ab2
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
