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प्रश्न
Factorise the following by taking out the common factors:
12a3 + 15a2b - 21ab2
उत्तर
12a3 + 15a2b - 21ab2
Here, the common factor is 3a.
Dividing throughout by 3a, we get
`(12"a"^3)/(3"a") + (15"a"^2"b")/(3"a") - (21"ab"^2)/(3"a")`
= 4a2 + 5ab - 7b2
∴ 12a3 + 15a2b - 21ab2
= 3a(4a2 + 5ab - 7b2).
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