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Factorise the Following by Taking Out the Common Factors: P(P2 + Q2 - R2) + Q(R2 - Q2 -p2) - R(P2 + Q2 - R2) - Mathematics

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प्रश्न

Factorise the following by taking out the common factors:
p(p2 + q2 - r2) + q(r2 - q2 -p2) - r(p2 + q2 - r2)

योग

उत्तर

p(p2 + q2 - r2) + q(r2 - q2 - p2) - r(p2 + q2 - r2)
= p(p2 + q2 - r2) - q(-r2 + q2 + p2) - r(p2 + q2 - r2)
= p(p2 + q2 - r2) - q(p2 + q2 - r2) - r(p2 + q2 - r2)
Here, the common factor is (p2 + q2 - r2).
Dividing throughout by (p2 + q2 - r2)

`("p"("p"^2 + "q"^2 - "r"^2))/("p"^2 + "q"^2 - "r"^2) - ("q"("p"^2 + "q"^2 - "r"^2))/(("p"^2 + "q"^2 - "r"^2)) - ("r"("p"^2 + "q"^2 - "r"^2))/(("p"^2 + "q"^2 - "r"^2))`
= p - q - r
∴ p(p2 + q2 - r2) + q(r2 - q2 - p2) - r(p2 + q2 - r2)
= (p2 + q2 - r2)(p - q - r).

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अध्याय 5: Factorisation - Exercise 5.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 5 Factorisation
Exercise 5.1 | Q 1.11
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