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प्रश्न
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
योग
उत्तर
The greatest common factor of the terms 2a4b4, -3a3b5 and 4a2b5 of the expression 2a4b4 - 3a3b5 + 4a2b5 is a2b4.
Now,
2a4b4 = a2b4 X 2a2
-3a3b5 = a2b4 X -3ab
4a2b5 = a2b4 X 4b
Hence, (2a4b4 - 3a3b5 + 4a2b5) can be factorised as [a2b4(2a2 - 3ab + 4b)].
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