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Question
Factorise.
63a2 − 112b2
Sum
Solution
63a2 − 112b2
On writing it as follows:
= 7(9a2 − 16b2)
= 7 [(3a)2 − (4b)2]
Using the identity a2 − b2 = (a − b) (a + b)
= 7(3a − 4b) (3a + 4b)
= a2 − b2
= (a − b) (a + b)
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