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Question
Factorise the following:
z² + 4z – 12
Solution
Product = −12, sum = 4
Split the middle term as 6z and – 2z
z² + 4z – 12 = z² + 6z – 2z – 12
= z(z + 6) – 2(z + 6)
= (z + 6)(z – 2)
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