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Karnataka Board PUCPUC Science 2nd PUC Class 12

[Fe(CN)6]4− and [Fe(H2O)6]2+ are of different colours in dilute solutions. Why? - Chemistry

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Question

[Fe(CN)6]4− and [Fe(H2O)6]2+ are of different colours in dilute solutions. Why?

Short Answer

Solution 1

The colour of a particular coordination compound depends on the magnitude of the crystal-field splitting energy, Δ. This CFSE in turn depends on the nature of the ligand. In case of [Fe(CN)6]4− and [Fe(H2O)6]2+, the colour differs because there is a difference in the CFSE. Now, CN is a strong field ligand having a higher CFSE value as compared to the CFSE value of water. This means that the absorption of energy for the intra d-d transition also differs. Hence, the transmitted colour also differs.

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Solution 2

In [Fe(CN)6]4−, CN is a strong field ligand hence, pairing of electrons takes place. 

In [Fe(H2O)6]4−, H2O is a weak ligand hence, pairing does not take place.

Because of their differing natures, these ligands show different magnitudes of crystal field splitting energy, resulting in varied wavelengths and colours.

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Chapter 9: Coordinate Compounds - Exercises [Page 259]

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NCERT Chemistry [English] Class 12
Chapter 9 Coordinate Compounds
Exercises | Q 21 | Page 259
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