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Find the 7th Term in the Expansion of ( 3 X 2 − 1 X 3 ) 10 . - Mathematics

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Question

Find the 7th term in the expansion of \[\left( 3 x^2 - \frac{1}{x^3} \right)^{10}\] .

 

Solution

We need to find the 7th term of the given expression.
Let it be T7
Now, we have  \[T_7 = T_{6 + 1}\]

\[= ^{10}{}{C}_6 (3 x^2 )^{10 - 6} \left( \frac{- 1}{x^3} \right)^6 \]
\[ =^{10}{}{C}_6 \left( 3^4 \right)\left( x^8 \right)\left( \frac{1}{x^{18}} \right)\]
\[ = \frac{10 \times 9 \times 8 \times 7 \times 81}{4 \times 3 \times 2 \times x^{10}} = \frac{17010}{x^{10}}\]

Thus, the 7th term of the given expression is \[\frac{17010}{x^{10}}\]

 
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Chapter 18: Binomial Theorem - Exercise 18.2 [Page 37]

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RD Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.2 | Q 2 | Page 37

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