Advertisements
Advertisements
Question
Find a single repeater machine that will do the same work as hook-up.
Solution
Using law of exponents, (am × an = am + n) ...[∵ a is non-zero integer]
Repeater machine can do the work is equal to 710 × 750 × 71 = 761
So, (× 761) single machine can do the same work.
APPEARS IN
RELATED QUESTIONS
`[(2/13)^-6 ÷ (2/13)^3]^3 xx (2/13)^-9` = ______.
Find the value of x so that (2–1 + 4–1 + 6–1 + 8–1)x = 1
Find the value of x–3 if x = (100)1 – 4 ÷ (100)0.
By what number should we multiply (–29)0 so that the product becomes (+29)0.
By what number should `((-3)/2)^-3` be divided so that the quotient may be `(4/27)^-2`?
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
The cells of a bacteria double in every 30 minutes. A scientist begins with a single cell. How many cells will be there after 24 hours?
Find a single repeater machine that will do the same work as hook-up.
Long back in ancient times, a farmer saved the life of a king’s daughter. The king decided to reward the farmer with whatever he wished. The farmer, who was a chess champion, made an unusal request:
“I would like you to place 1 rupee on the first square of my chessboard, 2 rupees on the second square, 4 on the third square, 8 on the fourth square, and so on, until you have covered all 64 squares. Each square should have twice as many rupees as the previous square.” The king thought this to be too less and asked the farmer to think of some better reward, but the farmer didn’t agree.
How much money has the farmer earned?
[Hint: The following table may help you. What is the first square on which the king will place at least Rs 10 lakh?]
Position of Square on chess board |
Amount (in Rs) |
1st square | 1 |
2nd square | 2 |
3rd square | 4 |
If a = – 1, b = 2, then find the value of the following:
ab – ba