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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Find adj(adj(A)) if adj A = [101020-101] - Mathematics

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Question

Find adj(adj(A)) if adj A = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]`

Sum

Solution

Given adj A = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]` to find adj(adj A)

Let adj A = B

∴ adj(adj A) = adj B

Now adj B = (Bij)T 

(i.e) B = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]`

(Bij) = `[(+|(2, 0),(0, 1)|, -|(0, 0),(-1, 1)|, +|(0, 2),(-1, 0)|),(-|(0, 1),(0, 1)|, +|(1, 1),(-1, 1)|, -|(1, 0),(-1, 0)|),(+|(0, 1),(2, 0)|, -|(1, 1),(0, 0)|, +|(1, 0),(0, 2)|)]`

= `[(+(2 - 0), -(0 - 0), +(0 + 2)),(-(0), +(1 + 1), -(0)),(+(0 - 2), -(0), +(2 - 0))]`

= `[(2, 0, 2),(0, 2, 0),(-2, 0, 2)]`

(Bij)T = `[(2, 0, -2),(0, 2, 0),(2, 0, 2)]`

(i.e) aj B = adj(adj A) = `[(2, 0, -2),(0, 2, 0),(2, 0, 2)]`

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Inverse of a Non-singular Square Matrix
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Chapter 1: Applications of Matrices and Determinants - Exercise 1.1 [Page 16]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 1 Applications of Matrices and Determinants
Exercise 1.1 | Q 10 | Page 16

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