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प्रश्न
Find adj(adj(A)) if adj A = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]`
उत्तर
Given adj A = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]` to find adj(adj A)
Let adj A = B
∴ adj(adj A) = adj B
Now adj B = (Bij)T
(i.e) B = `[(1, 0, 1),(0, 2, 0),(-1, 0, 1)]`
(Bij) = `[(+|(2, 0),(0, 1)|, -|(0, 0),(-1, 1)|, +|(0, 2),(-1, 0)|),(-|(0, 1),(0, 1)|, +|(1, 1),(-1, 1)|, -|(1, 0),(-1, 0)|),(+|(0, 1),(2, 0)|, -|(1, 1),(0, 0)|, +|(1, 0),(0, 2)|)]`
= `[(+(2 - 0), -(0 - 0), +(0 + 2)),(-(0), +(1 + 1), -(0)),(+(0 - 2), -(0), +(2 - 0))]`
= `[(2, 0, 2),(0, 2, 0),(-2, 0, 2)]`
(Bij)T = `[(2, 0, -2),(0, 2, 0),(2, 0, 2)]`
(i.e) aj B = adj(adj A) = `[(2, 0, -2),(0, 2, 0),(2, 0, 2)]`
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