Advertisements
Advertisements
Question
Find the distance between the following pair of point in the coordinate plane :
(5 , -2) and (1 , 5)
Solution
A (5 , -2) , B (1 , 5)
AB = `sqrt (("x"_2 - "x"_1)^2 + ("y"_2 - "y"_1)^2)`
`= sqrt ((1 - 5)^2 + (5 + 2)^2)`
`= sqrt (16+49)`
`= sqrt 65` units .
APPEARS IN
RELATED QUESTIONS
Find the coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, – 2) and (2, – 2). Also, find its circum radius
Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
Find the value of a when the distance between the points (3, a) and (4, 1) is `sqrt10`
Find the values of x, y if the distances of the point (x, y) from (-3, 0) as well as from (3, 0) are 4.
If the point P(x, y ) is equidistant from the points A(5, 1) and B (1, 5), prove that x = y.
Prove that the points (0,3) , (4,3) and `(2, 3+2sqrt 3)` are the vertices of an equilateral triangle.
Find a point on the y-axis which is equidistant from the points (5, 2) and (-4, 3).
The centre of a circle is (2x - 1, 3x + 1). Find x if the circle passes through (-3, -1) and the length of its diameter is 20 unit.
Point P (2, -7) is the centre of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of AB.
