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Question
Find `dy/dx if y = (sqrtx + 1/sqrtx)^2`
Solution
`y = (sqrtx + 1/sqrtx)^2`
∴ y = x + 2 + `1/x`
Differentiating w.r.t. x, we get
`dy/dx=d/dx(x + 2 + 1/x)`
= `d/dx(x) + d/dx (2) + d/dx(1/x)`
= `1+0+d/dx(x^(-1))`
= 1 + (–1) x–2
= `1 – 1/x^2`
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