Advertisements
Advertisements
Question
Find the greatest common factor (GCF/HCF) of the following polynomial:
36a2b2c4, 54a5c2, 90a4b2c2
Solution
The numerical coefficients of the given monomials are 36, 54 and 90. The greatest common factor of 36, 54 and 90 is 18.
The common literals appearing in the three monomials are a and c.
The smallest power of a in the three monomials is 2.
The smallest power of c in the three monomials is 2.
The monomial of common literals with the smallest powers is a2c2.
Hence, the greatest common factor is 18a2c2.
APPEARS IN
RELATED QUESTIONS
Work out the following division:
10y(6y + 21) ÷ 5(2y + 7)
Work out the following division:
96abc(3a − 12)(5b − 30) ÷ 144(a − 4) (b − 6)
Divide as directed.
52pqr (p + q) (q + r) (r + p) ÷ 104pq (q + r) (r + p)
Factorise the expression and divide them as directed.
(m2 − 14m − 32) ÷ (m + 2)
Factorise the expression and divide them as directed.
5pq(p2 − q2) ÷ 2p(p + q)
Find the greatest common factor (GCF/HCF) of the following polynomial:
a2b3, a3b2
Divide: 6x3 − 13x2 − 13x + 30 by 2x2 − x − 6
Find the quotient and the remainder when :
3x4 + 6x3 − 6x2 + 2x − 7 is divided by x − 3. verify your answer.
Divide x6 – y6 by the product of x2 + xy + y2 and x – y.