Advertisements
Advertisements
Question
Find the mean of all odd numbers from 5 to 20. Find the new mean when each number is multiplied by 4.
Solution
The numbers are:
5, 7, 9, 11, 13, 15, 17, 19
`barx = (x_1 + x_2 + x_3 + .... + x_n)/n`
n = 8
⇒ `barx = (5 + 7 + 9 + 11 + 13 + 15 + 17 + 19)/8 `
⇒ `barx = 96/8`
⇒ `barx = 12`
Therefore, Mean of odd numbers from 5 to 20 = 12
If numbers are multiplied by 4, the numbers are:
20,28, 36, 44, 52, 60, 68, 76
`barx = (x_1 + x_2 + x_3 + .... + x_n)/n`
n = 8
⇒ `barx = (20 + 28 + 36 + 44 + 52 + 60 + 68 + 76 )/8`
⇒ `barx = 384/8`
⇒ `barx = 48`
Therefore, Mean of odd numbers from 5 to 20 when multiplied by 4= 48
APPEARS IN
RELATED QUESTIONS
Find the mode and the median of the following frequency distribution:
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
The marks obtained by 120 students in a mathematics test is given below:
Marks | No. of students |
0 – 10 | 5 |
10 – 20 | 9 |
20 – 30 | 16 |
30 – 40 | 22 |
40 – 50 | 26 |
50 – 60 | 18 |
60 – 70 | 11 |
70 – 80 | 6 |
80 – 90 | 4 |
90 – 100 | 3 |
Draw an ogive for the given distributions on a graph sheet. Use a suitable scale for your ogive. Use your ogive to estimate:
- the median
- the number of student who obtained more than 75% in test.
- the number of students who did not pass in the test if the pass percentage was 40.
- the lower quartile.
The distribution, given below, shows the marks obtained by 25 students in an aptitude test. Find the mean, median and mode of the distribution.
Marks obtained | 5 | 6 | 7 | 8 | 9 | 10 |
No. of students | 3 | 9 | 6 | 4 | 2 | 1 |
Find the mean of first 10 prime numbers.
Find the mean of the following frequency distribution :
class | 0-6 | 6-12 | 12-18 | 18-24 | 24-30 |
Frequency | 7 | 5 | 10 | 12 | 6 |
Find the mean of the following frequency distribution by the step deviation method :
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 | 120-140 |
Frequency | 12 | 24 | 52 | 88 | 66 | 42 | 16 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks (less than) | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
No. of students | 5 | 15 | 30 | 54 | 72 | 86 | 94 | 100 |
Find the median of:
63, 17, 50, 9, 25, 43, 21, 50, 14 and 34
Find the mean of: 7, 5, 0, 3, 0, 6, 0, 9, 1 and 4
The measures of central tendency may not lie between the maximum and minimum values of data.