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Question
Find n, if `"n"/(8!) = 3/(6!) + 1/(4!)`
Solution
`"n"/(8!) = 3/(6!) + 1/(4!)`
∴ `"n"/(8!)=3/(6!)+(6xx5)/(6xx5xx4!)`
∴ `"n"/(8!)=3/(6!)+30/(6!)`
∴ `"n"/(8xx7xx6!) = 33/(6!)`
∴ `"n"/56` = 33
∴ n = 56 × 33 = 1848
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