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Question
Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.
Solution
Radius of ground state of hydrogen atom
= 0.53 Å = 0.53 x 10-10 m
According to de Brogile relation
2πr = nλ
For ground state n = 1
2 x 3.14 x 0.53 x 10-10 = 1 x λ
∴ λ = 3.32 x 10-10 m
= 3.32 Å
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