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Question
Find the point on x-axis which is equidistant from points A(-1,0) and B(5,0)
Solution
Let P (x ,0) be the point on . x- axis Then
AP = BP ⇒ AP2 = BP2
`⇒ (x+1)^2 + (0-0)^2 = (x-5)^2 +(0-0)^2`
`⇒ x^2 +2x+1=x^2-10x +25`
`⇒ 12x = 24 ⇒ x = 2`
Hence , x = 2
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