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Question
Find the ratio in which the point P (2, 4) divides the line joining points (-3, 1) and (7, 6).
Solution
Let the point P divides AB in the ratio k : 1.
Coordinates of P are
x = `(7"k" - 3)/("k" + 1)`
y = `(6"k" + 1)/("k" + 1)`
But given, P(x, y) =P(2, 4)
`therefore 2 = (7"k" - 3)/("k" + 1)`
⇒ 2k + 2 = 7k - 3
⇒ 5 = 5k
⇒ k = 1
k : 1 = 1 : 1
or `4 = (6"k" + 1)/("k" + 1)`
4k + 4 = 6k + 1
⇒ 3 = 2k
⇒ k = `3/2`
k : 1=3 : 2
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Complete the following activity to find the coordinates of point P which divides seg AB in the ratio 3:1 where A(4, – 3) and B(8, 5).
Activity:
∴ By section formula,
∴ x = `("m"x_2 + "n"x_1)/square`,
∴ x = `(3 xx 8 + 1 xx 4)/(3 + 1)`,
= `(square + 4)/4`,
∴ x = `square`,
∴ y = `square/("m" + "n")`
∴ y = `(3 xx 5 + 1 xx (-3))/(3 + 1)`
= `(square - 3)/4`
∴ y = `square`