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Question
Find the surface area of a cuboid whose length = 6 dm, breadth = 8 dm, height = 10 dm.
Solution
\[\text { Dimensions of the cuboid: }\]
\[\text{ Length = 6 dm } \]
\[\text { Breadth = 8 dm } \]
\[\text { Height = 10 dm } \]
\[\text { Surface area of the cuboid }= 2 \times (\text { length } \times \text { breadth + breadth } \times \text { height + length }\times\text { height })\]
\[ = 2 \times (6 \times 8 + 8 \times 10 + 6 \times 10)\]
\[ = 2 \times (48 + 80 + 60)\]
\[ = 376 {dm}^2 \]
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