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Question
Find the area of a right triangle whose hypotenuse is 10 cm and one of the acute angle is 24°24′
Solution
In the ΔABC,
sin 24°24′ = `"AB"/"AC"`
0.4131 = `"AB"/10`
∴ AB = 4.131 cm
In the ΔABC,
cos 24°24′ = `"BC"/"AC"`
0.9107 = `"BC"/10`
∴ BC = 9.107 cm
Area of the right angle = `1/2 xx "BC" xx "AB"`
= `1/2 xx 9.107 xx 4.131`
= `37.62/2`
Area of the triangle = 18.81 cm2
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